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Fig. 2 Sward composition as a function of N rate in 1995 and 1996. Error bars are standard error of the mean. 1995 chicory = (-3.89 x 10-4)(N rate)2 + (0.19)(N rate) + 41.36, R2 = 0.86; 1996 chicory = (3.26 x 10-5)(N rate)2 - (0.09)(N rate) + 37.26, R2 = 0.87; 1995 grasses = (2.31 x 10-4)(N rate)2 - (0.06)(N rate) + 28.04, R2 = 0.84; 1996 grasses = (-4.59 x 10-5)(N rate)2 + (0.09)(N rate) + 59.11, R2 = 0.84; 1995 legumes = (1.84 x 10-4)(N rate)2 - (0.15) (N rate) + 28.73, R2 = 0.95; 1996 legumes = (3.37 x 10-5) (N rate)2 - (0.02)(N rate) + 3.71, R2 = 0.69
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